tanh(x, out=None, where=None, **kwargs)¶
Compute hyperbolic tangent element-wise.
-1j * mt.tan(1j*x).
- x : array_like
- Input tensor.
- out : Tensor, None, or tuple of Tensor and None, optional
- A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated tensor is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
- where : array_like, optional
- Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.
- y : Tensor
- The corresponding hyperbolic tangent values.
If out is provided, the function writes the result into it, and returns a reference to out. (See Examples)
 M. Abramowitz and I. A. Stegun, Handbook of Mathematical Functions. New York, NY: Dover, 1972, pg. 83. http://www.math.sfu.ca/~cbm/aands/  Wikipedia, “Hyperbolic function”, http://en.wikipedia.org/wiki/Hyperbolic_function
>>> import mars.tensor as mt
>>> mt.tanh((0, mt.pi*1j, mt.pi*1j/2)).execute() array([ 0. +0.00000000e+00j, 0. -1.22460635e-16j, 0. +1.63317787e+16j])
>>> # Example of providing the optional output parameter illustrating >>> # that what is returned is a reference to said parameter >>> out1 = mt.zeros(1) >>> out2 = mt.tanh([0.1], out1) >>> out2 is out1 True
>>> # Example of ValueError due to provision of shape mis-matched `out` >>> mt.tanh(mt.zeros((3,3)),mt.zeros((2,2))) Traceback (most recent call last): ... ValueError: operands could not be broadcast together with shapes (3,3) (2,2)