mars.tensor.tan

mars.tensor.tan(x, out=None, where=None, **kwargs)[source]

Compute tangent element-wise.

Equivalent to mt.sin(x)/mt.cos(x) element-wise.

x : array_like
Input tensor.
out : Tensor, None, or tuple of Tensor and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated tensor is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
where : array_like, optional
Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.

**kwargs

y : Tensor
The corresponding tangent values.

If out is provided, the function writes the result into it, and returns a reference to out. (See Examples)

M. Abramowitz and I. A. Stegun, Handbook of Mathematical Functions. New York, NY: Dover, 1972.

>>> from math import pi
>>> import mars.tensor as mt
>>> mt.tan(mt.array([-pi,pi/2,pi])).execute()
array([  1.22460635e-16,   1.63317787e+16,  -1.22460635e-16])
>>>
>>> # Example of providing the optional output parameter illustrating
>>> # that what is returned is a reference to said parameter
>>> out1 = mt.zeros(1)
>>> out2 = mt.cos([0.1], out1)
>>> out2 is out1
True
>>>
>>> # Example of ValueError due to provision of shape mis-matched `out`
>>> mt.cos(mt.zeros((3,3)),mt.zeros((2,2)))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid return array shape