mars.tensor.divide

mars.tensor.divide(x1, x2, out=None, where=None, **kwargs)[source]

Divide arguments element-wise.

x1 : array_like
Dividend tensor.
x2 : array_like
Divisor tensor.
out : Tensor, None, or tuple of Tensor and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
where : array_like, optional
Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.

**kwargs

out : Tensor
The quotient x1/x2, element-wise. Returns a scalar if both x1 and x2 are scalars.

Equivalent to x1 / x2 in terms of array-broadcasting.

Behavior on division by zero can be changed using seterr.

In Python 2, when both x1 and x2 are of an integer type, divide will behave like floor_divide. In Python 3, it behaves like true_divide.

>>> import mars.tensor as mt
>>> mt.divide(2.0, 4.0).execute()
0.5
>>> x1 = mt.arange(9.0).reshape((3, 3))
>>> x2 = mt.arange(3.0)
>>> mt.divide(x1, x2).execute()
array([[ NaN,  1. ,  1. ],
       [ Inf,  4. ,  2.5],
       [ Inf,  7. ,  4. ]])
Note the behavior with integer types (Python 2 only):
>>> mt.divide(2, 4).execute()
0
>>> mt.divide(2, 4.).execute()
0.5
Division by zero always yields zero in integer arithmetic (again, Python 2 only),
and does not raise an exception or a warning:
>>> mt.divide(mt.array([0, 1], dtype=int), mt.array([0, 0], dtype=int)).execute()
array([0, 0])
Division by zero can, however, be caught using seterr:
>>> old_err_state = mt.seterr(divide='raise')
>>> mt.divide(1, 0).execute()
Traceback (most recent call last):
...
FloatingPointError: divide by zero encountered in divide
>>> ignored_states = mt.seterr(**old_err_state)
>>> mt.divide(1, 0).execute()
0