bitwise_and(x1, x2, out=None, where=None, **kwargs)¶
Compute the bit-wise AND of two tensors element-wise.
Computes the bit-wise AND of the underlying binary representation of the integers in the input arrays. This ufunc implements the C/Python operator
- x1, x2 : array_like
- Only integer and boolean types are handled.
- out : Tensor, None, or tuple of Tensor and None, optional
- A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated tensor is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
- where : array_like, optional
- Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.
- out : array_like
logical_and bitwise_or bitwise_xor
The number 13 is represented by
00001101. Likewise, 17 is represented by
00010001. The bit-wise AND of 13 and 17 is therefore
000000001, or 1:
>>> import mars.tensor as mt
>>> mt.bitwise_and(13, 17).execute() 1
>>> mt.bitwise_and(14, 13).execute() 12 >>> mt.bitwise_and([14,3], 13).execute() array([12, 1])
>>> mt.bitwise_and([11,7], [4,25]).execute() array([0, 1]) >>> mt.bitwise_and(mt.array([2,5,255]), mt.array([3,14,16])).execute() array([ 2, 4, 16]) >>> mt.bitwise_and([True, True], [False, True]).execute() array([False, True])